Given:
Density = .92 g / cm³
Volume = 1.8 kg
= (1.8 * 1000) grams
= 1800 grams
Now,
\(Density (d) = \frac{Mass (m)}{volume(v)}\)
\(volume (v)= \frac{mass(m)}{density(d)}\)
\(volume (v)= \frac{1800}{.92}\)
\(volume (v)= 1956.521739\)
\(volume (v)= 1956.5~ cm^{3}\)
So, the volume of 1.8 kg of ice is 1956.5 cm³
