V-9/10v+6=11(hlp)this problem is confusing.
\(\frac{v-9}{10v} +6=11\)
Subtracting 6 on both sides, we get,
\(\frac{v-9}{10v} =11-6\)
\(\frac{v-9}{10v} =5\)
Multiplying by 10v on both sides , we get,
\(\frac{v-9}{10v}*10v =5 *10v\)
\(v-9=50v\)
\(-9 = 50v -v\)
\(-9=49v\)
\(\frac{-9}{49} =v\)
\(v=- \frac{9}{49}\)
\(\frac{v-9}{10v+6}=11 \\\\ 11(10v+6)=v-9 \\\\ 110v+66=v-9 \\\\ 110v-v=-9-66 \\\\ 109v= -75 \\\\ \boxed{v=-\frac{75}{109}}\)