what is the product? (4y − 3)(2y2 3y − 5)a. 8y3 3y 15b. 8y3 − 23y 15c. 8y3 − 6y2 − 17y 15d. 8y3 6y2 − 29y 15
\((4y-3)(2 y^{2} +3y-5) \\ =4y(2 y^{2} +3y-5)-3(2 y^{2} +3y-5) \\ =8 y^{3} +12 y^{2} -20y-6 y^{2} -9y+15 \\ =8 y^{3} +6 y^{2} -29y +15\)
Answer:D!
Step-by-step explanation:
On Egde..Ur welcome