a light bulb has a resistance of 360 . what is the current in the bulb when it has a potential difference of 120 v across it? 0.33 a 3 a 480 a 43,200 a
Presume we are looking for the current:
V = IR
120 = I*360
120/360 = I
1/3 = I
I = 1/3 = 0.333..
Current ≈ 0.33 Ampere.
Answer:
i = 0.33 A
Explanation:
As per ohm's law we know that voltage across any ohmic resistor is product of resistance and current through it
So it is given as
\(V = i R\)
now we know that
V = 120 Volts
R = 360 ohm
so here we have
\(120 = 360 \times i\)
\(i = \frac{1}{3} A\)