the pressure of gas in a cylinder is 70 kilopascals. if the volume of the cylinder is reduced from 8.0 liters to 4.0 liters, what should be the pressure of the gas in the cylinder?

Verified Answer :

By Boyle's law:

P₁V₁ = P₂V₂

708 = P₂4

P₂4 = 708

P₂ = 70*8/4 = 140

P₂ = 140 kiloPascals.

Answer:

140 kilopascals

Explanation: