the pressure of gas in a cylinder is 70 kilopascals. if the volume of the cylinder is reduced from 8.0 liters to 4.0 liters, what should be the pressure of the gas in the cylinder?
By Boyle's law:
P₁V₁ = P₂V₂
708 = P₂4
P₂4 = 708
P₂ = 70*8/4 = 140
P₂ = 140 kiloPascals.