Verified Answer :

Edufirst

In the reactants Sb has oxidatin number 0 (because it is in its elemental form)

In the products Sb has oxidaton number +3.

Then Sb lost electrons which means it oxidized.

in the following reaction, Sb is oxidized.
2Sb (s) + 6H2SO4 (as) → Sb2(SO4)3 + 3SO2 + 6H2O

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