Verified Answer :

Kunchan

(x - a)^2 + (y - b)^2 = c^2
above equation is the general equation for the circle. In that, a and b are center of the circle and c is the radius of the circle.

let's change the equation to general circle equation
(x - 3)^2 + (y - 5)^2 = 25
(x - 3)^2 + (y - 5)^2 = 5^2

center (3 , 5) 
x = 3
y = 5

Answer:

The equation \((x+3)^2+(y-5)^2=25\)  has coordinates for the center (-3, 5)

Step-by-step explanation:

Given : Equation of circle as  \((x+3)^2+(y-5)^2=25\)

We have to fins the coordinates for the center for this circle.

 

The standard equation of circle with center (h,k) and radius r is given as

\((x-h)^2+(y-k)^2=r^2\)

Consider the given equation \((x+3)^2+(y-5)^2=25\)

25 can be written as 5²

Rewrite it in standard form as ,

\((x-(3))^2+(y-5)^2=5^2\)

where center is (-3, 5) and radius = 5

Thus, The equation \((x+3)^2+(y-5)^2=25\)  has center (-3, 5) and radius = 5

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