Answer:
The value of (f-g)(2)= 14
Step-by-step explanation:
f(x) = 3x^2 + 1 and g(x) = 1 – x
we need to find the value of (f-g)(2)
(f-g)(x)= f(x) - g(x)
Replace f(x) and g(x)
\((f-g)(x)= f(x) - g(x)= (3x^2+1 -(1-x))= 3x^2+1-1+x= 3x^2+x\)
Now plug in 2 for x
\((f-g)(x) =3x^2+x\)
\((f-g)(2) =3(2)^2+2=12+2=14\)
The value of (f-g)(2)= 14
