Kirsten built a rectangular corral with a fence on three sides.A side of the barn served as a short side od the corral.She used 130 m of fencing . The length of the corral was 20 m longer than the width . Find the dimensions of the corral. Choices for the width : 25, 30 , 35 EXPLAIN
L = W + 20
2L + W = 130
Solve that system with each of the width values. Aka: plug in each w and solve for the length. Whichever w value gets the same L value for both equations is the answer.
Answer: Second option is correct.
Step-by-step explanation:
Since we have given that
Let the width of corral be 'w'.
Let the length of corral be 'w+20'
Perimeter of corral = 130 m
As we know the formula for "Perimeter":
\(Perimeter=2l+w\\\\130=2(w+20)+w\\\\130=2w+40+w\\\\130=3w+40\\\\130-40=3w\\\\90=3w\\\\\dfrac{90}{3}=w\\\\w=30\ m\)
so, width of corral = 30 m
Length of corral = 30+20 = 50 m
Hence, Second option is correct.