How long is the arc intersected by a central angle of 5pi/3 radians in a circle with a radius of 2 ft? Round your answer to the nearest tenth. Use 3.14 for pi

A2.6 ft
B7.0 ft
C10.5 ft
D31.4 ft

Verified Answer :

Length of an arc of a circle:
L = n / 2π ·2 ·r · π 
L = (5π/3 ·2 ·2 ·3.14 ) : 2π = 5/3 · 6.28 = 10.47 ≈ 10.5
Answer: C) 10.5 ft.

Answer:

C


Step-by-step explanation:

The arc length formula (in radians) is:

\(s=r\theta\)

Where,

  • \(s\) is the arc length
  • \(r\) is the radius of the circle
  • \(\theta\) is the angle intercepted by the arc [in radians]

It is given that radius, \(r=2\)  and angle, \(\theta=\frac{5\pi}{3}\)


Substituting these values in the arc length formula gives us:

\(s=(2)(\frac{5\pi}{3})\\s=\frac{10\pi}{3}\)

Using \(\pi\)  as \(3.14\) and rounding to nearest tenth gives us:

\(s=\frac{(10)(\pi)}{3}\\s=10.5\)  ft

Correct answer is C.