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coralsnonsense coralsnonsense
  • 10-10-2014
  • Mathematics
Answered

Please help. (1/x)<2. It says to concider 2 cases. I already got x>(1/2).
How do I find another case.

Verified Answer :

konrad509
konrad509 konrad509
  • 10-10-2014

\(\frac{1}{x}<2|\cdot x^2\\ x<2x^2\\ 2x^2-x>0\\ x(2x-1)>0\\ x\in(-\infty,0)\cup(\frac{1}{2},\infty)\)

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