The endpoints of EF¯¯¯¯¯ are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of EF¯¯¯¯¯? (xF2,yF2) (xE2,yE2) (xE+xF2,yE+yF2) (xE+xF2,yE+yF2)
The coordinates of the midpoint of EF are:
M ( \(\frac{xE+xF}{2}, \frac{yE+yF}{2}\) )
Answer: The correct option is (D) \(\left(\dfrac{xE+xF}{2},\dfrac{yE+yF}{2}\right).\)
Step-by-step explanation: Given that the co-ordiantes of the end-points of segment EF are E(xE, yE) and F(xF, yF) respectively.
To find the co-ordinates of the mid-point of EF.
We know that
the co-ordinates of the mid-point of a line segment with end-points A(a, b) and B(c, d) are given by
\(\left(\dfrac{a+c}{2},\dfrac{b+d}{2}\right).\)
Therefore, the co-ordinates of the mid-point of segment Sf will be
\(\left(\dfrac{xE+xF}{2},\dfrac{yE+yF}{2}\right).\)
Thus, (D) is the correct option.