Answer:
Equation of line is given by:
y = mx+b; ......[1] where m is the slope and b is the y-intercept.
Given the equation of a line: \(9x-3y =15\)
Subtract 9x from both sides we get;
\(9x-3y-9x =15-9x\)
Simplify:
\(-3y =15-9x\)
or
\(-3y =-9x+15\)
Divide by -3 both sides we get;
\(y = \frac{-9x+15}{-3}\)
or
\(y = \frac{-9x}{-3} + \frac{15}{-3}\)
Simplify:
\(y = 3x - 5\)
On comparing with equation [1] we have;
m = 3
Therefore, the slope of the graph of the following \(9x-3y =15\) is, 3
