The hypotenuse of an isosceles triangles measures 10 inches long. What is the length of one leg of the triangle?
the leg sides are or at least one is (10 in.)/√(2) = 10√(2)/2 in. = 5√(2) long.
Let one leg be x. Hypotenuse = 10
x² + x² = 10²
2x² = 10²
2x² = 100
x² = 100/2
x² = 50
x = √50
x = √(25 2)
x = √25 √2 = 5√2
x = 5√2 ≈ 5*1.414 = 7.07
Length of each leg ≈ 7.07