Answer: f(3) =6
Step-by-step explanation:
Given: A sequence is defined by the recursive function
\(f(n+1)=f(n)-2\)
f(1)= 10
Then f(2) can be written as
\(f(2)=f(1+1)\\\\\Rightarrow f(2)=f(1)-2\\\\\Rightarrow f(2)=10-2\\\\\Rightarrow f(2)=8\)
Similarly, f(3) can be written as
\(f(3)=f(2+1)\\\\\Rightarrow f(3)=f(2)-2\\\\\Rightarrow f(3)=8-2\\\\\Rightarrow f(3)=6\)
Therefore, the value of f(3) =6.
