Answer:
Value of \(x =\frac{6}{11}\)
Step-by-step explanation:
Given the equation: \(1331x^3 -216 =0\) .....[1]
Addition property of equality states that you add the number to both sides of an equation.
Add 216 to both sides of an equation [1]
\(1331x^3 -216+216 =0+216\)
Simplify
\(1331x^3=216\)
As,we know that \(11 \times 11 \times 11 =11^3 = 1331\) and \(6 \times 6 \times 6 =6^3 = 216\)
then the given equation becomes;\(11^3x^3=6^3\)
or
\((11x)^3=6^3\) ......[2]
Using \(a^3=b^3\) then a=b.
[2] ⇒
11x =6
Divide both sides of an equation by 11, we get
\(\frac{11x}{11} =\frac{6}{11}\)
Simplify:
\(x =\frac{6}{11}\)
therefore, the value of x is, \(\frac{6}{11}\)
