Answer: The required perimeter of the rectangle is 32 ft.
Step-by-step explanation: Given that a rectangle has a length of 10 ft. and a width of 6 ft.
We are to find the perimeter of the rectangle.
We know that
the perimeter of a rectangle with length l units and width w units is given by
\(P=2(l+w).\)
For the given rectangle, we have
length, l = 10 ft. and width, w = 6 ft.
Therefore, the perimeter of the rectangle is
\(P=2(l+w)=2(10+6)=2\times16=32.\)
Thus, the required perimeter of the rectangle is 32 ft.
