what value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?
Answer:
x ∈ IR / \(x\geq -2\) or you can also write
x ∈ IR / x ∈ [-2 , + ∞)
Step-by-step explanation:
We have the following inequality :
\(2(3x-1)\geq 4x-6\)
To find the solution set of the inequality we need to find the values of x that satisfy the inequality.
Working with the inequality :
\(2(3x-1)\geq 4x-6\)
\(6x-2\geq 4x-6\)
\(2x\geq -4\)
\(x\geq \frac{-4}{2}\)
\(x\geq -2\)
The solutions of the inequality are all real numbers greater or equal to -2
We can write this as
x ∈ IR / \(x\geq -2\)
Or either using and interval as
x ∈ IR / x ∈ [-2 , + ∞)