Verified Answer :

JeanaShupp

Answer: 6 combinations.


Step-by-step explanation:

Given :- Total number of players= 4

Then, combination of players can a coach have if he needs to pick 2 out of total players=\(^4C_2=\frac{4!}{2!2!}\)

\(=\frac{4\times3\times2\times1}{2\times2}\)

\(=6\)

Therefore, there are 6 combinations of players can a coach have if he needs to pick 2 out of total players of 4.

There are 6 combinations of players can a coach have if he needs to pick 2 out of the total players 4.

We have given that,

6 combinations.

Total number of players= 4

We have to determine what combination of players can a coach have if he needs to pick 2 out of the total players,

What is the combination?

\(_n C_r=\frac{n !}{r ! (n-r) !}\\_n C_r = \ number \ of \ combinations\ = \ total \ number \ of \ objects\ in \ the \ set\\r = \ number \ of \ choosing \ objects \from \ the \ set\)

\(C(4,2)=\frac{4!}{2!2!}\)

\(C(4,2)=6\)

Therefore, there are 6 combinations of players can a coach have if he needs to pick 2 out of the total players 4.

To learn more about the combination visit:

https://brainly.com/question/295961

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