Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form. What is the value of c in her equation
Standard form for quadratic equations is:
ax² + bx + c = 0
Therefore, in Mischa's equation, the value of c is -7.
Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form
The standard form of quadratic equation is
\(y= ax^2 + bx + c\)
When y=0 then the standard equation becomes
\(0= ax^2 + bx + c\)
Now we compare the given equation \(0 = -x^2 + 4x - 7\) with \(0= ax^2 + bx + c\) and find the value of a, b,c
-x^2 can be written as -1x^2
\(0= ax^2 + bx + c\)
\(0 = -1x^2 + 4x - 7\)
a= -1 , b=4 and c=-7
The value of c is -7