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  • 24-06-2016
  • Physics
Answered

A particular planet has a moment of inertia of 9.74 × 1037 kg•m2 and a mass of 5.98 × 1024 kg. Based on these values, what is the planet’s radius?

Verified Answer :

Anonymous Anonymous
  • 24-06-2016

assuming the planet can be treated as a solid sphere,\(I=\frac{2}{5}MR^2\)

(9.74 x 10^37 kg-m²) = (2/5)(5.98 x 10^24 kg)R²

R = 6.38 x 10^6 m

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