Jim paddles from one shore of a lake 3 miles wide at 4 mph, and John paddles from the opposite shore a 5 pmh. How long will they travel before they meet
Let the time they both travel be x hours.
By the time they both meet, the distance covered by both would be equal to the width of the river.
Distance = Speedtime
The 4 mph after x hours would have traveled = 4x
The 5 mph after x hours would have traveled = 5x
Total distance traveled = 4x + 5x = 3
9x = 3
x = 3/9
x = 1/3 hours = 1/3 60 minutes = 20 minutes
They would have both traveled 20 minutes as at when they meet.
T = time that each will paddle before they meet
D = distance paddled by JIm
(3 - D) = distance paddled by John
D = 4T --- Equation 1
and
(3 - D) = 5T or
D = 3 - 5T --- Equation 2
Since Equation 1 = Equation 2
4T = 3 - 5T
9T = 3
T =1/3 hr = 20 minutes
ANSWER -- Jim and John will be paddling for 20 minutes before they pass each other