Answer:
6(cos 0° + sin 0° . i)
Step-by-step explanation:
The trigonometric form formula is a combination of the following formulas:
Binomic: a + bi
Polar: rα
Giving as a result the formula: r (cos α + sin α · i)
Where,
r = module
α = angle
In the given case, the complex number is 6, where
Binomic form: 6 + 0i
Where a = 6 and b = 0
We must calculate the module (r) and the angle (α).
\(r=\sqrt{a^{2} +b^{2}} =\sqrt{6^{2} +0^{2}}=\sqrt{36}=6\)
α = \(tan^{-1}(0)\) = 0°
Since r=6 and α=0°, then the trigonometric form is
r(cos α + sin α · i) = 6(cos 0° + sin 0° . i)
Hope this helps!
