Answer:
Acceleration of the rock is 1.64 m/s²
Explanation:
It is given that,
Initial speed of the rock, u = 0
Final speed of the rock, v = 4.9 m/s
Time taken by a rock, t = 3 seconds
We have to determine the acceleration of the rock. The acceleration of the rock is equal to the rate of change of velocity. Mathematically, it can be written as :
\(a=\dfrac{v-u}{t}\)
\(a=\dfrac{4.9\ m/s-0}{3\ s}\)
\(a=1.633\ m/s^2\)
\(a=1.64\ m/s^2\)
So, the acceleration of the rock is 1.64 m/s². Hence, this is the required solution.
