Verified Answer :

JoshEast

\(2NH_{3} + H_{2} SO _{4} ----\ \textgreater \ (NH _{4} )_{2} SO _{4}\)

mole ratio of sulfuric acid : ammonium sulphate =  1 :  1
    ∴ if mole of  "          "   = 60.0 mol
     then mole of ammomium sulphate = 60.0 mol

Mass of ammonium sulphate  =  molar mass    moles
                                                =   [(2 1) + (1 32) + (4 16)]    60.0 mol
                                                =  98 g/mol    60.0 mol
                                                =  5880 g

portt

How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia? D. 7,930 g

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