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Answered

The reaction below shows how silver chloride can be synthesized.



AgNO3 + NaCl mc017-1.jpg NaNO3 + AgCl



How many moles of silver chloride are produced from 15.0 mol of silver nitrate?



1) 1.0 mol


2) 15.0 mol


3) 30.0 mol


4) 45.0 mol

Verified Answer :

JoshEast

\(AgNO_{3} _{(aq)} + NaCl_{(aq)} ----\ \textgreater \ NaNO_{3} _{(aq)} + AgCl _{(aq)}\)
mole ration of \(AgCl _{(aq)} : AgNO_{3} _{(aq)}\) =  1 : 1

∴ if moles of  \(AgNO_{3} _{(aq)}\) =  15.0 mol
then   "      "     \(AgCl _{(aq)}\)  =  15.0 mol

∴  the Option  2 is the answer.

Answer : The correct option is, (2) 15.0 mole

Solution : Given,

Moles of silver nitrate = 15.0 mole

The given balanced chemical reaction is,

\(AgNO_3+NaCl\rightarrow NaNO_3+AgCl\)

By the stoichiometry, we conclude that 1 mole of silver nitrate react with 1 mole of sodium chloride to give 1 mole of sodium nitrate and 1 mole of silver chloride.

Th ratio \(AgNO_3:AgCl=1:1\)

From the balanced reaction, we conclude that

As, 1 mole of silver nitrate react to give 1 mole of silver chloride

So, 15 moles of silver nitrate react to give 15 moles of silver chloride

Therefore, the number of moles of silver chloride produced are, 15.0 mole

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