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At most, Alana can spend $40 on carnival tickets. Ride tickets cost $4 each, and food tickets cost $2 each. Alana buys at least 16 tickets. The system of inequalities represents the number of ride tickets, r, and the number of food tickets, f, she buys.


r + f ≥ 16


4r + 2f ≤ 40




What is the maximum number of ride tickets she can buy?


4

6

10

12

Verified Answer :

W0lf93

We can let r be the number of food tickets and f be the number of food tickets.

Since Alana can spend at most $40, that means the total of price bought for r and f must be less than or equal to $40. In addition, since Alana buys at least 16 tickets, this also means that the total of r and f is 16. Mathematically, we have these inequalities:

(1) 4r + 2f ≤ 40 and
(2) r + f ≥ 16

Multiplying -2 in (2), we have

4r + 2f ≤ 40
-2r - 2f ≤ 32

Adding both inequalities,

2r ≤ 8
r ≤ 4

Since r must be less than or equal to 4.Thus the answer is A.

Answer:

A

Step-by-step explanation:

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