What is the factored form of 64g^3+8
Answer:
\((4g+2)(16g^2-8g+4)\)
Step-by-step explanation:
The given expression is \(64g^3+8\)
Let us write this expression in perfect cube form
\((4g)^3+(2)^3\)
Use the formula of sum of cubes which is given by
\(a^3+b^3=(a+b)(a^2-ab+b)^2\)
Here, a= 4g, b = 2
\((4g)^3+(2)^3= (4g+2)((4g)^2-(4g)(2)+2^2\\\\=(4g+2)(16g^2-8g+4)\)
Thus, the factored form of the given expression is
\((4g+2)(16g^2-8g+4)\)