At a railway yard, locomotives are used to haul containers carrying oil. A locomotive is chosen according to the volume of oil it can haul, as shown in the table.

Locomotive

Capacity

A450 0−750 cubic feet

CG35 750−1,500 cubic feet

BR73 1,500−2,500 cubic feet

YH61 2,500−3,500 cubic feet

The four cylindrical containers listed in the table need to be hauled.

Cylinder

Length (ft.)

Diameter (ft.)

Fill Level

A 40 12 half

B 24 8 full

C 16 16 full

D 6 12 full

Match each container to the locomotive needed to haul it.

Tiles

A450

cylinder A

CG35

cylinder B

BR73

cylinder C

YH61

cylinder D

Volume of cylinder A = π(12^2/4) x (40/2) = 2,262 cubic feet which will be hauled by locomotive BR73.
Volume of cylinder B = π(8^2/4) x 24 = 1,206 cubic feet which will be hauled by locomotive CG35.
Volume of cylinder C = π(16^2/4) x 16 = 3,217 cubic feet which will be hauled by locomotive YH61.
Volume of cylinder D = π(6^2/4) x 12 = 339 cubic feet which will be hauled by locomotive A450.

Answer Link

ayfat23 ayfat23 · Answer 2 · 2022-07-07T06:42:11-04:00

We can compare the volume with how they are going to be overhauled as :

cylinder A :locomotive BR73.

cylinder B :locomotive CG35.

Cylinder C ;locomotive YH61.

Cylinder D :locomotive A450.

What is Volume of cylinder ?

We can calculate the volume of the cylinder using the formula π\(r^{2}\)h as :

For cylinder A:

\(\pi *12^{\frac{2}{4} } *20 =2262 ft^{3}\)

For cylinder B;

\(\pi *8^{\frac{2}{4} } *24 =1206 ft^{3}\)

For cylinder C;

\(\pi *16^{\frac{2}{4} } *16 =3217 ft^{3}\)

For cylinder D:

\(\pi *6^{\frac{2}{4} } *12 =339 ft^{3}\)

Then we can compare the volume with how they are going to be overhauled as :

cylinder A :locomotive BR73.

cylinder B :locomotive CG35.

Cylinder C ;locomotive YH61.

Cylinder D :locomotive A450.

Learn more on volume of the cylinder at ; https://brainly.com/question/9554871

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