Answer-
\(\left(3x-6\right)\left(2x^2-7x+1\right)=6x^3-33x^2+45x-6\)
Solution-
Given the two polynomials are \(3x-6, 2x^2 -7x+1\)
So their product will be,
\(=\left(3x-6\right)\left(2x^2-7x+1\right)\)
Distributing the Parentheses,
\(=3x\cdot \:2x^2+3x\left(-7x\right)+3x\cdot \:1+\left(-6\right)\cdot \:2x^2+\left(-6\right)\left(-7x\right)+\left(-6\right)\cdot \:1\)
Applying minus-plus rules,
\(=3\cdot \:2x^2x-3\cdot \:7xx+3\cdot \:1\cdot \:x-6\cdot \:2x^2+6\cdot \:7x-6\cdot \:1\)
Simplifying further,
\(=6x^3-33x^2+45x-6\)
