Answer: Our solutions are x= -7 or x = 6.
Step-by-step explanation:
Since we have given that
\(x^2+x-30=12\)
We need to find the solutions to the above equations:
First we calculate the constants:
\(x^2+x-30=12\\\\x^2+x-30-12=0\\\\x^2+x-42=0\)
Now, we will split the middle term:
\(x^2+x-42=0\\\\x^2+7x-6x-42=0\\\\x(x+7)-6(x-7)=0\\\\(x+7)(x-6)=0\)
As we know that
a.b=0
⇒either a = 0 or b = 0
\((x+7)=0\ or\ (x-6)=0\\\\x=-7,6\)
So, our solutions are x= -7 or x = 6.
