Verified Answer :

taskmasters

Completing
the square is done as follows:

  1. Write the equation in a way that the constants are in the right side while

the terms with x are on the left. 

10x2 + 40x = 13



  1. Make sure that the coefficient of the x^2 term is 1.
    10(x^2 + 4x) = 13

  2. Adding a term to both sides that will complete the square in the left

side. This is done by dividing the coefficient of the x term by 2 and squaring
it. Note: The same amount should be added to the right side to balance the
equation.
10(x^2 + 4x + 4) =13 +40

10(x+2)^2 = 53

Therefore, the value of A is 10.

calculista

we have

\(10x^{2} + 40x - 13 = 0\)

Group terms that contain the same variable, and move the constant to the opposite side of the equation

\(10x^{2} + 40x =13\)

Factor the leading coefficient

\(10(x^{2} + 4x) =13\) ----------> the value of A is \(10\)

Complete the square. Remember to balance the equation by adding the same constants to each side

\(10(x^{2} + 4x+4) =13+40\)

\(10(x^{2} + 4x+4) =53\)

Rewrite as perfect squares

\(10(x+2)^{2} =53\)

\(10(x+2)^{2} =53 \\ (x+2)^{2} =\frac{53}{10} \\ \\ x+2=(+/-)\sqrt{\frac{53}{10}} \\ \\ x1=-2+\sqrt{\frac{53}{10}}\\ \\ x2=-2-\sqrt{\frac{53}{10}}\)

therefore

the answer is

the value of A is \(10\)

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