Three multiplied by the sum of 4 and a number is the same as 18 more than the number. Find the number.. . If n is \"the number,\" which equation could be used to solve for the number?. . . 3n + 4 = n + 18. 4(3 + n) =n + 18. 3(4 + n) =n + 18. 3(4 + n) + 18 > n
Translate the statement to algebraic language:
1) Call x the unknown number
2) The sum of 4 and a number = 4 + x
3) Three multiplied by the sum of 4 and a number = 3(4 + x)
4) Is the same as 18 more than the number: 3( 4 + x) = 18 + x
Solve the equation:
3*4 + 3x = 18 + x
3x - x = 18 - 12
2x = 6
x = 6/3
x = 2.
The number is 2.
Answer:
3(n+4)=n+18
The value of n is 3
Step-by-step explanation:
Let n be the required number.
Sum of 4 and the number n is (n +4)
Three multiplied by the sum of 4 and the number= 3(n +4)
Now, 18 more than the number = (n + 18)
From, the given directions, we can write the equation
\(3(n+4)=n+18\)
Now, we solve this equation for n
Distribute 3 over the parenthesis
\(3n+12=n+18\)
Subtract n to both sides
\(2n+12=18\)
Subtract 12 to both sides
\(2n=6\)
Divide both sides by 2
\(n=3\)
Therefore, the required equation is
3(n+4)=n+18
The value of n is 3