Quadrilateral ABCD is inscribed in a circle. m angle A is 64°, m angle B is (6x + 4)°, and m angle C is (9x - 1)°. What is m angle D?
B and D are opposite angles, so they're supplementary.
m∠B + m∠D = 180°
82° + m∠D = 180°
m∠D = 98°
Answer:
\(m
Step-by-step explanation:
we know that
The Inscribed Quadrilateral Theorem, states that a quadrilateral is inscribed in a circle if and only if the opposite angles are supplementary
so
In this problem
\(m -----> equation B
we have
\(m
\(m
Step 1
Find the value of x
substitute the measure of angle A and the measure of angle C in the equation A to find x
\(64\°+(9x-1)\°=180\°\)
\(9x=180\°-64\°+1\°\)
\(9x=117\°\)
\(x=13\°\)
Step 2
Find the measure of angle D
substitute the measure of angle B in the equation B to find m<D
\((6x+4)+m
substitute the value of x
\((6(13)+4)+m
\(82\°+m
\(m