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A charged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 10.5 cm, giving it a charge of -22.3 µC.. . (a) Find the magnitude of the electric field just inside the paint layer. (b) Find the magnitude of the electric field just outside the paint layer. (c) Find the magnitude of the electric field 5.00 cm outside the surface of the paint layer.

Verified Answer :

meerkat18

The formula that will be used in this problem is E = q/ 4pir^2 z where z is the elctric charge constant equal to 8.854  10 ^-12. The magnitude using r equal to 0.0525 m and q equal to -22.3 10^-6 C is equal to -22.3 10^-6/ 4pi(0.0525)^2 8.854  10 ^-12 or equal to -7.272 10 ^7. The magnitude 5 cm outside the surface is -22.3 10^-6/ 4pi(0.0525+0.05)^2 8.854  10 ^-12 equal to -1.908 *10^7. 

saadhussain514

Since it is hard to write the mathematics equations here so i would like to share it in a picture

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