Verified Answer :

brookegallagher

\(\frac{4 x^{2} +20x+25}{2x+5} \\ \frac{(2x+5)(2x+5)}{2x+5} \\ 2x+5\)

Simplified, it is equal to 2x+5.

To get your answer, you factor the numerator. Then, when you get (2x+5)²/(2x+5), you cancel out one of the 2x+5 in the numerator with the one in the denominator and get your answer.

Hope this helps!

Ckaranja

\(\frac{ 4x^{2}+20x+25 }{2x+5}\)
Factoring numerator;
\(\frac{ 4x^{2}+10x+10x+25 }{2x+5}\)
\(\frac{2x(2x+5)+5(2x+5)}{2x+5}\)
\(\frac{(2x+5)+(2x+5)}{2x+5}\)
=2x+5

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