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Lily sold 18 items at the street fair. She sold bracelets for $6 each and necklaces for $5 each for a total of $101. Which system of equations can be used to find b, the number of bracelets she sold, and n, the number of necklaces she sold?

Verified Answer :

I had the same question. But here is the answer:
b + n = 18
6b + 5n = 101

TaeKwonDoIsDead

Answer:

\(n+b=18\)   and   \(6b+5n=101\)


Step-by-step explanation:

Two 2 system of equations are the ones about:

  • Total number of items sold
  • Total price of items sold

Total number of items sold:

Lily sold 18 items.

Since \(b\) is the number of bracelets and \(n\) is the number of necklaces, we can write:

\(b+n=18\)


Total price of items sold:

Bracelets are $6 each and Lily sold @@MATH_TOKEN_5@@ of them. So total is @@MATH_TOKEN_6@@ for bracelets.

Necklaces are $5 each and Lily sold \(n\) of them. So total is \(5n\) for necklaces.

In total she sold all of them for $101, so we can write:  \(6b+5n=101\)


The system of equations, thus, are:

\(n+b=18\) ,   and

\(6b+5n=101\)

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