By using the following reactions, calculate the heat of combustion of pentane:

C5H12 (g) + 8O2 (g) → 5CO2 (g) + 6H2O (l).




C (s) + O2 (g) → CO2 (g), ΔH = –395 kJ

H2 (g) + 1/2O2 (g) → H2O (l), ΔH = –285 kJ

5C (s) + 6H2 (g) → C5H12 (g), ΔH = –147 kJ



–6.80 × 103 kJ



–2.85 × 103 kJ



–5.42 × 103 kJ



–3.54 × 103 kJ