How many moles of Ba(NO3)2 are there in 0.25 L of a 2.00 M Ba(NO3)2 solution?
Answer : The number of moles of \(Ba(NO_3)_2\) are 0.50 moles.
Solution : Given,
Volume solution = 0.25 L
Molarity of solution = 2.00 mole/L
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
\(Molarity=\frac{\text{ Number of moles of solute}}{\text{ Volume of solution}}\)
Now put all the given values in this formula, we get number of moles.
\(2.00mole/L=\frac{\text{ number of moles of }Ba(NO_3)_2}{0.25L}\)
By rearranging the term,
Number of moles of \(Ba(NO_3)_2\) = 0.50 moles
Therefore, 0.50 moles of \(Ba(NO_3)_2\) are there in the solution.
Answer:
the answer is 0.50 mol
Explanation:
because that's the answer