The balanced chemical reaction:
2H2 + O2 = 2H2O
We are given the amount of the reactant to be used for this reaction. These values will be the starting point of the calculations. First, we need to fine the limiting reactant.
10.54 g H2 ( 1 mol H2 / 2.02 g H2 ) = 5.22 mol H2
95.10 g O2 ( 1 mol O2 / 32 g H2 ) = 2.97 mol O2
The limiting reactant is the hydrogen gas. We use this value for further calculations.
5.22 mol H2 ( 2 mol H2O / 1 mol H2 ) ( 18.02 g / 1 mol ) = 188.13 g H2O
