Answered

A 1.0 M H2S solution has a pH = 3.75 at equilibrium. What is the value of Ka?


3.16 × 10−21


3.16 × 10−8


8.89 × 10−5


8.89 × 10−8

Verified Answer :

When H2S dissociates, the equation is H2S= 2H+ + S2-. In this case, the H+ concentration can be determined from the pH 3.75. taking 10^-pH, H+ is equal to 1.7783 x10^-4 M. Ka is expressed [H+]^2[S2-]/[H2S], this is equal to [1.7783 x10^-4 M]^2 [1.7783 x10^-4 M]/ [1.0-1.7783 x10^-4 M] or 5.62 x10^-12.

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