Answer:
Dividing \(\frac{m^2n^3}{p^3}\) by \(\frac{mp}{n^2}\) is \(mn^5p^{-4}\)
Step-by-step explanation:
Divide \(\frac{m^2n^3}{p^3}\) by \(\frac{mp}{n^2}\)
Solution :
We divide first expression by another,
\(=\frac{\frac{m^2n^3}{p^3}}{\frac{mp}{n^2}}\)
\(=\frac{m^2n^3}{p^3}\times \frac{n^2}{mp}\)
\(=\frac{m^2n^5}{mp^4}\)
\(=m^{2-1}n^5p^{-4}\)
\(=mn^5p^{-4}\)
Therefore, Dividing \(\frac{m^2n^3}{p^3}\) by \(\frac{mp}{n^2}\) is \(mn^5p^{-4}\)
