The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. suppose intensity is 8000 units at a distance of 2 miles. what will the intensity be at a distance of 11 miles? round your answer to the nearest unit.
Let I represent intensity and and d the distance; I\(\alpha \frac{1}{ d^{2} }\) When I=8000 8000=\(\frac{k}{4}\) k=32000 I=\(\frac{32000}{d}\) I=\(\frac{32000}{121}\) I=265 units
