Katelynfortney
Answered

glucose is an important sugar in many biochemical reactions what is the molarity of a solution that contains 500 grams of glucose (molecular weight= 180.16 g/mol) in 7.02 liters of solution

A.56M
B.78 M
C3.85 M
B4.98 M

Verified Answer :

Willchemistry

Number of moles :

500 / 180.16 => 2.775 moles

Volume = 0.72 L

M = n / V

M = 2.775 / 0.72

M = 3.85 M

hope this helps!

lucainkviedma

Answer:

The correct answer is c.

Explanation:

First, look for the same problem to verify that the correct volume is 0.702 L.

Now we must calculate the amount of glucose moles (n) in the 500g:

n = \(\frac{500 g}{180 \frac{g}{mol} }\)

n = 2,7 mol

Molarity is given by moles of compound per liter. In this way, we calculate the molarity (M) as:

M = \(\frac{2,7 mol}{0,702 L}\)

M = \(3,85\frac{mol}{L}\)

Have a nice day!

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