21-06-2016
Mathematics

Answered

find the derivative of: sqrt( 3x+sqrt( 3x+sqrt( 3x)))

Verified Answer :

24-06-2016

Hello,

y'=\(( \sqrt{3x+ \sqrt{3x+ \sqrt{3x} } } )'\)

\(y'=\dfrac{(3+\frac{1}{2\sqrt{3x+\sqrt{3x}}})*(3+\frac{3}{2\sqrt{3x}})}{2( \sqrt{3x+ \sqrt{3x+ \sqrt{3x} } } )}\)

This make me think of a Ramanuyan 's formula of (x+1)

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