First, find the slope,
\(m= \frac{y-y_1}{x-x_1}\)
\(m= \frac{10-2}{-6-12}\)
\(m= -\frac{4}{9}\)
Now using point slope form, pick a coordinate, I'll pick (12,2)
\(y-y_1=m(x-x_1)\)
\(y-2=- \frac{4}{9} (x-12)\)
\(y=-\frac{4 x}{9}+\frac{22}{3}\)
Now, when x-intercept, 'y' will be 0,
\(0=-\frac{4 x}{9}+\frac{22}{3}\)
\(x= \frac{33}{2}\)
