Wave A has an amplitude of 3, and wave B has an amplitude of 3. What will happen when the trough of wave A meets the trough of wave B?
The answer is: They will interfere to create a trough with an amplitude of 6.
Answer:
\(A_r=6.\)
Explanation:
It is given that both wave have same amplitude i.e \(A=3.\)
Now, we need to find what will happen to the waves when trough of wave A meets the trough of wave B.
It means that both waves are in same phase i.e, the phase difference between them is 0 degree.
We know resultant amplitude \(A_r\) of two waves of same amplitude A with phase difference \(\theta\) is given by.
\(A_r=2\times A \times cos\dfrac{\theta}{2}.\)
In this case , A=3 and \(\theta=0^o.\)
Putting value of A and \(\theta\) in above equation.
We get, \(A_r=6.\)
Therefore, a new wave will form of resultant amplitude of 6.
Hence, it is the required solution.