Let
D-------> discriminant of a quadratic equation
we know that
The discriminant of a quadratic equation is equal to
\(D=b^{2} -4ac\)
In this problem
we have
\(-2x^{2} + 6x + 13=0\\ \\ a=-2\\ b=6\\c=13\)
Substitute the values in the formula above
\(D=6^{2} -4*(-2)*(13)\)
\(D=36+104\)
\(D=140\)
therefore
the answer is
the value of the discriminant is \(140\)
