Answer: The molarity of the solution is 3 M.
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
\(Molarity=\frac{n\times 1000}{V_s}\)
where,
n= moles of solute
\(Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{87.75g}{58.44g/mol}=1.50mole\)
\(V_s\) = volume of solution in ml = 500 ml
\(Molarity=\frac{1.50\times 1000}{500}=3M\)
The molarity of a solution that contains 87.75 g of NaCl in 500 mL of solution is 3 M.
