Answer
Starting from Monomial
\(1. 16 x^6=2\times 2\times 2\times 2\times x^2\times x^2\times x^2\)
in the factor of monomial , Number ,2 is more than 3 n, where, n=1,2,3,....., that is it is appearing four times. So, it is not a perfect cube.
\(2.27 x^8=3\times 3\times 3\times x^3\times x^3\times x^2\)
The power of x should be multiple of 3.
Not a perfect cube.
\(3. 32 x^{12}=2\times 2\times 2\times 2\times 2\times x^4\times x^4\times x^4\)
Number 2, should be equal to , 3 n, but here,it is equal to 5 times.So,
Not a perfect cube.
\(4.64 x^6=4\times 4\times 4\times x^2\times x^2\times x^2=(4)^3\times (x^2)^3\)
Perfect cube.
Option D
